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statics problems and solutions chapter 2

The same applies to the trolley in Figure 2.5(b). Any two of these quantities can be determined when the rest are known. << /Filter /FlateDecode /Length 19006 /Length1 53261 >> The push of the wind acting on the sign board in Figure 2.2(b) ia a distributed force. Determine the magnitude of the... 2.2-127: Determine the angle u between the two cables attached to the pipe. endobj Please sign in or register to post comments. (b) by sketching the polygon of forces and then calculating the values required using geometrical calculations. Two common problems in statics involve either finding the resultant force, knowing its components, or resolving a known force into two or three components. Download Free Statics Problems And Solutions Chapter 2 Statics Problems And Solutions Chapter 2 As recognized, adventure as skillfully as experience about lesson, amusement, as competently as arrangement can be gotten by just checking out a ebook statics problems and solutions chapter 2 furthermore it is not directly done, you 8 0 obj 2.2-91: Determine the magnitude and coordinate direction angles of the resu... 2.2-92: If FB = 560 N and FC = 700 N, determine the magnitude and coordinat... 2.2-93: If FB = 700 N, and FC = 560 N, determine the magnitude and coordina... 2.2-94: The tower is held in place by three cables. In many cases, the area of application is extremely small compared to the dimensions of the body being upon acted by the force. 2.2-128: Determine the magnitudes of the components of F acting along and pe... 2.2-129: Determine the magnitude of the projected component of F along AC . 3 0 obj endobj The added forces, F and –F, do not give rise to any external effects on the body which the forces act on. The addition of vectors illustrated by the equation given above can also be carried out graphically by using the triangle rule, Figure 2.7. Let the position vector r that points from P to Q describes the relative position between P and Q. ADDITION OF FORCES. This textbook survival guide was created for the textbook: Engineering Mechanics: Statics, edition: 13. b), we have, FAC= 24002 + 6002 - 2(400)(600) cos 30°=322.97 lb. 0 0 0 0 0 0 0 0 0 0 Trigonometry. This fact is formulated from experience into what is called the principle of transmissibility which states that: The overall effect of the action of an external force on a rigid body is dependent only on the magnitude, direction, and line of action of the force. Ans: If necessary, the principle of transmissibility can be applied as shown in Figure 2.6(b). Engineering and Tech - Textbook Survival Guide, Key Engineering and Tech Terms and definitions covered in this textbook. From the diagram, we obtain the relationship, However, from Figure 2.11(b), we can formulate the relationships  r1 = x1i + y1j + z1k and r2 = x2i + y2j + z2k. FORMULATION OF A MOMENT USING VECTORS, 2.15. Applying the law of cosines by referring to Fig. 0 0 0 0 0 0 615 0 459 0 If P is the resultant of F1, F2, F3, … hence, =  (F1x + F2x + …)i + (F1y + F2y + …)j + (F1z + F2z + …)k, = ΣFixi + ΣFiyj + ΣFizk                                                                                                                 …..(2.5). Hence the resolution involves six quantities, i.e. Engineering Mechanics: Statics was written by and is associated to the ISBN: 9780132915540. As an illustration, consider the structure portrayed in Figure 2.1. The parallelogram law of addition is shown in Fig. endobj 1 0 obj Any force F can be written in the form of a Cartesian vector. 0 0 0 0 0 0 0 0 0 0 Trigonometry:Using the law of sines (Fig.b), we have. If the force F is made to slide along its line of action from A to a new point of application B, the values of the reactions exerted by the support surface on the structure do not change. Determine the magnitude... 2.2-27: The beam is to be hoisted using two chains. 2–1. Express this for... 2.2-99: Determine the magnitude and coordinate direction angles of the resu... 2.2-100: The guy wires are used to support the telephone pole. of force Fand its direction .u. The magnitude of a force is a scalar quantity. It is stressed that a concentrated force is a vector quantity and the force obeys the laws of vector algebra. When force F is resolved into perpendicular directions, we obtain the rectangular components. A concentrated force is a vector quantity. U����0��J_��e������|�^_$�m��ㄻM�ْn��T��?�VUP���c7��.gt��H���k0�~��L?��3�Q��U�i��c�[f���%��H���6�A��s�?g�B��!�\�@t���7c�Q��H�gU��牁�Z��� X�>�mRH����H����#��*�� ~��txfNx��Kz�� �O��"L��ؙ5E|l b. H�\��j�0��~ In the case of planar forces, the resultant can also be obtained by drawing the vectors of the forces head-to-tail to form the respective force polygon, Figure 2.9. D... 2.2-9: Resolve F1 into components along the u and v axes and determine the... 2.2-10: Resolve F2 into components along the u and v axes and determine the... 2.2-11: The force acting on the gear tooth is F = 20 lb.

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